http://gabrielecirulli.github.io/2048/
arguably the most productivity-killing time-waster i have ever played since n v2 came out
still, my life is complete now
![Image](http://i7.minus.com/jAJvj2RnXoxCR.png)
Please ignore this person.▲▪►▪▼◄▲ wrote:I have this many posts now.
ok i'll do it for you. i haven't checked the source code but i'm going to trust you when you said the 4's appear with 10% probability.EddyMataGallos wrote:Regarding score possibilities:
If only 2 tiles were to appear, the minimum score needed to build a 2048 tile would be 20480 (2048 + 2*1024 + 4*512 + ... = 2048*10, because the initial 2's don't count towards the score), but that would be perfect ensamblation, however since you have a 10% chance of having a 4 tile to appear, you can substract 10% of the 4's row that will appear on their own, that is 204.8, hence 20275.2 should be the average minimum score required. Seems like I was lucky with my initial 4's :P
18432 would be technically minimum with 100% initial 4's, which is obviously very unlikely to happen (at least 1/10^510 probability, since 510 is the minimum number of movements you'll need to make to make it to the 2048, as each time you make a move, the sum of tiles on the board increases by at most 4, actually always by 4 in this ideal situation, but in a real situation it would take almost double as most tiles are 2's).
Now I'm too lazy to calculate the chance of getting a sub-20k average, but it doesn't seem too low, with a clean technique you would probably get it after 3 wins or so.
Haha well played :P999_Springs wrote:psh. i beat 4096 LAST MONTH. the ball is in your court, eddymatagallos. :P oh, and without any undos. let me take this very rare opportunity to point and laugh at you.
ok i'll do it for you. i haven't checked the source code but i'm going to trust you when you said the 4's appear with 10% probability.
to get a score of under 20000, you said 18432 is the minimum score with all 4's, so the number of 2's you'd be limited to at most would be (20000-18432)/2 = 784. then to make 2048 you'd need the rest of them to be 4's, so that's (2048-2*784)/4 = 120 fours. keep in mind this is a lower bound for the number of fours and you'd most likely need several more 4's than this, since even assuming perfect play, when you do the 2->4->8->...->1024 thing at the end that's 10 more steps that give you tiles that merge together and give you more points, but i'll ignore those.
to get the chances of getting at least 120 fours with a 10% probability of each occurring within the first 902 tiles you use a binomial calculator which tells you there is a < 1/1000 chance of getting 120 or more fours, and it drops rapidly if you ask for even a few more fours.
so yeah, i really doubt you'll ever beat it with sub-20000. :P
of course, using the undo function on 2048-undo a lot of times until you get however many 4's you wanted would obviously work, but that's cheating.
Indeed it is, that was my first completion there and I thought that it might have been big luck, but my second completion was also sub-20k and its not particularly clean:999_Springs wrote:ios/android devices have a way higher 4 spawn rate. this is pretty obvious if you're actually playing it for a while. also it makes it much harder to get 4096 or 8192, because random 4 spawns that don't go with the 2s on the board are often what kills you. i have a screenshot of 2048 on android with <20000 which i'll edit in this post as soon as i find my usb cable
i almost got 16384 on pc :(
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