Does 2/6 Equal 1/3?
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- Tetris
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There's an extra assumption. a and b are real numbers, but they must also be different numbers, otherwise you multiply by 0 in the second line (multiply both sides by (a-b), which =0 if a=b). This means that when you get to the 'either/or' choice at the end, you cannot choose the one that leads to 'a=b' because that goes against your rules when choosing a and b.

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I have an excuse for saying that, but that excuse is also embarrassing.

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Mathematical point of view: yes, 1/3=2/6
My brother's point of view: well, if you went back in time and only cut the pizza into 3 parts instead of 6, and gave him one, he would still have the same amount. (basically the mathematical POV, he wanted me to post his point on it, cmon...hes 9)
Idiot point of view= NO!!! 1 and 3 aren't the same as 2 and 6
it really is a theoretical questions
(hey, this was to degrade into unintelligence some time, why not now?) :D


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That's an awful wishy-washy way of putting it. Can't say that's unexpected coming from a Brit -- when you want the job done and done right good, you get a 'Merican.iangb wrote:It took me a good five minutes to work that out, Suki. You properly nerd sniped me.
SolutionThere's an extra assumption. a and b are real numbers, but they must also be different numbers, otherwise you multiply by 0 in the second line (multiply both sides by (a-b), which =0 if a=b). This means that when you get to the 'either/or' choice at the end, you cannot choose the one that leads to 'a=b' because that goes against your rules when choosing a and b.
It sets two solutions equal to each other.
It's wrong for the same reason the following is wrong:
9 = 9
(3)^2 = (-3)^2
3 = -3

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2/6 = o.333333 recurring.
Problem solved


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I have to admit that proof thoroughly puzzled me. Even though I figured out what the problem was, I can't quite explain why it's wrong. Your explanation solves the problem, but is that really true?Tsukatu wrote:It sets two solutions equal to each other.
It's wrong for the same reason the following is wrong:
9 = 9
(3)^2 = (-3)^2
3 = -3
If you've got x^2 = y^2 and you know nothing else about x and y, then your above solution would suggest that nothing can be said about x and y directly. But that's not true, is it? Can't we go a bit further and say that either x = y or x = -y? Then, as iangb implied, we would try 2 different cases: a = b and a != b. a = b would yield two trivial results (a+b=t and a=b), and a != b would yield a trivial result (a+b=t) and a wrong result (a=b, wrong because it contradicts an assumption). I'm not entirely sure that my initial step relating x and y covers all cases, though. Would you mind elaborating on your explanation?
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x^2 = y^2
|x|=|y|
...And I still can't get over how unbelievably retarded my post was. u_u;;

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Well if that is what you want except for the invalid part. here you go.incluye wrote:Yes, we need more unnecessary, mathematically invalid answers to this question. Thank you.
i^(-i)=sqrt(e^(pi))
An imaginary number raised to the opposite of its self is equal to the square root of a transcendental number raised to another transcendental number. Crazy huh?
If anyone wants to post the proof using Eulers work.
*note* this has no baring to what incluye said, or to the discussion at hand. But to make it relevant I propose that since imaginary numbers can equal real numbers 2/6 has to equal 1/3.
<@gloomp> Holy sweet, balls run.
<@Izzy> Sweet, balls run holy.
<@gloomp> Run sweet, balls holy.
<@Izzy> Sweet run, ballsy hole.
<@gloomp> All's sweet, holeb run.
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This time, you cut the pizza into 3 parts, and you get 1 of the pieces. But you would rather have smaller pieces so you cut the pizza into 6 pieces, and take 2. You have the same amount of pizza.
Here's the problem with the pizza thing though, the inability to put the pizza back together adds a variable to the whole problem, so really...it's an invalid argument.


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And therein lies the paradox that allows blizz to troll now 6 pages.Qwubble wrote: Here's the problem with the pizza thing though, the inability to put the pizza back together adds a variable to the whole problem, so really...it's an invalid argument.
<@gloomp> Holy sweet, balls run.
<@Izzy> Sweet, balls run holy.
<@gloomp> Run sweet, balls holy.
<@Izzy> Sweet run, ballsy hole.
<@gloomp> All's sweet, holeb run.
<@Izzy> Ballsy nun, sweet mole.

<@Kool> bro no joke, I saw the sexiest swedish chick giving herself anal on one of those pop-up alarm-clocks at my uncle's house
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I...I think I might have been reading the wrong page.incluye wrote:Yes, we need more unnecessary, mathematically invalid answers to this question. Thank you.
Sorry for any misunderstanding.

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